[Rasch] 3=4 theorem

Steven L. Kramer skramer1958 at verizon.net
Wed Jul 11 21:35:13 EST 2007

```[Rasch] 3=4 theoremTo be more specific:
4*(a+b-c)=3*(a+b-c) can be rewritten as
4*0=3*0  (since a+b=c)

You can't go from 4*0=3*0 to 4=3.

----- Original Message -----
From: Stephanou, Andrew
To: rasch at acer.edu.au
Sent: Wednesday, July 11, 2007 6:54 AM
Subject: FW: [Rasch] 3=4 theorem

Division by zero is not allowed.

------------------------------------------------------------------------------
From: rasch-bounces at acer.edu.au on behalf of Rama Guinda
Sent: Tue 7/10/2007 9:31 PM
To: rasch
Subject: [Rasch] 3=4 theorem

Sorry, I know it's rather irrelevent. But I can't believe it! And I can't
find the flaw in the reasoning either. Besides, I don't know who to ask.
Thanks
Rama

Three is equal to four
Theorem: 3=4
Proof:

Suppose:
a + b = c

This can also be written as:
4a - 3a + 4b - 3b = 4c - 3c

After reorganizing:
4a + 4b - 4c = 3a + 3b - 3c

Take the constants out of the brackets:
4 * (a+b-c) = 3 * (a+b-c)

Remove the same term left and right:
4 = 3

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