[Rasch] 3=4 theorem

Steven L. Kramer skramer1958 at verizon.net
Wed Jul 11 21:35:13 EST 2007


[Rasch] 3=4 theoremTo be more specific:
4*(a+b-c)=3*(a+b-c) can be rewritten as
4*0=3*0  (since a+b=c)

You can't go from 4*0=3*0 to 4=3.


  ----- Original Message ----- 
  From: Stephanou, Andrew 
  To: rasch at acer.edu.au 
  Sent: Wednesday, July 11, 2007 6:54 AM
  Subject: FW: [Rasch] 3=4 theorem


  Division by zero is not allowed.


------------------------------------------------------------------------------
  From: rasch-bounces at acer.edu.au on behalf of Rama Guinda
  Sent: Tue 7/10/2007 9:31 PM
  To: rasch
  Subject: [Rasch] 3=4 theorem


  Sorry, I know it's rather irrelevent. But I can't believe it! And I can't
  find the flaw in the reasoning either. Besides, I don't know who to ask.
  Could you please help?
  Thanks
  Rama

  Three is equal to four
  Theorem: 3=4
  Proof:

  Suppose:
  a + b = c

  This can also be written as:
  4a - 3a + 4b - 3b = 4c - 3c

  After reorganizing:
  4a + 4b - 4c = 3a + 3b - 3c

  Take the constants out of the brackets:
  4 * (a+b-c) = 3 * (a+b-c)

  Remove the same term left and right:
  4 = 3

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