[Rasch] 3=4 theorem

Looveer, Juho Juho.Looveer at det.nsw.edu.au
Wed Jul 11 23:15:19 EST 2007


The flaw is that:
1.    a + b = c
2.  therefore a + b - c = 0
3.  when dividing or multiplying by zero, it invalidates the equation

Dr Juho Looveer
Manager, Data Collection
Planning and Innovation
NSW Department of Education and Training
Level 5, 35 Bridge St Sydney
GPO Box 33
Sydney NSW 2001
work phone: 956 18192
work fax: 956 18055
Juho.Looveer at det.nsw.edu.au 



-----Original Message-----
From: rasch-bounces at acer.edu.au on behalf of Rama Guinda
Sent: Wed 11/07/2007 7:31 PM
To: rasch at acer.edu.au
Subject: [Rasch] 3=4 theorem
 
Sorry, I know it's rather irrelevent. But I can't believe it! And I can't 
find the flaw in the reasoning either. Besides, I don't know who to ask.
Could you please help?
Thanks
Rama

Three is equal to four
Theorem: 3=4
Proof:

Suppose:
a + b = c

This can also be written as:
4a - 3a + 4b - 3b = 4c - 3c

After reorganizing:
4a + 4b - 4c = 3a + 3b - 3c

Take the constants out of the brackets:
4 * (a+b-c) = 3 * (a+b-c)

Remove the same term left and right:
4 = 3

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